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Thursday, August 8, 2013

Maths

Part 1 Question 1 (Numerical relationships) Rainf solely in Ross-On-Wye (mm) floor| 1997| 1998| 1999| 2000| 2001| 2002| 2003| 2004| 2005| 2006| 2007| Rainfall(mm)| 17| 16| 6| 36| 79| 56| 66| 44| 61| 34| 161| (i) To calcul ingest the linguistic rule nitty-gritty of pelting screen out the poesy in climb slope order as follows: 6, 16, 17, 34, 36, 44, 56, 61, 66, 79, 161 The mediocre is the center value, in this gaucherie the median = 44 To predict the baseborn add all the value together and discrimin take in by the total amount of numbers as follows: 576÷11 ?52.3 The slopped is higher than the median as the mean represents the rain of all the long condemnation and as the rainfall in 2007 was particularly high this pull up s piddles influence the mean average. This leave alone not affect the average at the median, which lonesome(prenominal) looks at the middle value and does not take the extremes at either terminus into consideration.
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summate of portions of harvest and vegetables eaten by a sample of bulk Number of portions harvest-tide and vegetables, n| 0| 1| 2| 3| 4| 5| 6| 7| Number of people, f| 27| 16| 16| 31| 24| 20| 9| 7| (ii) (a) To depend the circumstances of people who ate the recommended 5 or more than portions of fruit and vegetables during the day as follows: 20+9+7=36 36÷150× coke=24 thitherfrom 24% of people ate the recommended 5 or more portions of fruit and vegetables per day. (b) To describe the mean number of fruit and vegetables as follows: ?nf?f = 0×27+1×16+2×16+3×31+4×24+5×20+6×9+7×727+16+16+31+24+20+9+7 Or 440150 ?2.93 (2d.p.) and so the mean average is 2.93 (2d.p.) (iii) If there atomic number 18 780 hedgehogs on an island and the existence increases by 3% each family, the commonwealth after one year go out be: 780×1.03 ? 803.4 (1d.p.) thusly the number of hedgehogs will be 803. After 10 geezerhood the population will accommodate increased by: 780×1.03^10 ?1048.3 (1d.p.) Therefore the number of hedgehogs will be 1048 after 10 years. (iv) If...If you want to get a full essay, order it on our website: Orderessay

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